(2x^2y)dx=(3x^3+y^2)

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Solution for (2x^2y)dx=(3x^3+y^2) equation: 


Simplifying
(2x2y) * dx = (3x3 + y2)

Remove parenthesis around (2x2y)
2x2y * dx = (3x3 + y2)

Multiply x2y * dx
2dx3y = (3x3 + y2)

Remove parenthesis around (3x3 + y2)
2dx3y = 3x3 + y2

Solving
2dx3y = 3x3 + y2

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '2x3y'.
d = 1.5y-1 + 0.5x-3y

Simplifying
d = 1.5y-1 + 0.5x-3y

Reorder the terms:
d = 0.5x-3y + 1.5y-1

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